How to convert Numbers to words i.e., 44 = fourty four
Posted on August 16, 2011
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 | 'String Manipulation - How to convert Numbers to words i.e., 44 = fourty four Option Explicit 'Return a string of words to represent the integer part of this value. Public Function NumbersToWords(ByVal num As Currency) As String Dim power_value(1 To 5) As Currency Dim power_name(1 To 5) As String Dim digits As Integer Dim result As String Dim i As Integer ' Initialize the power names and values. power_name(1) = "trillion": power_value(1) = 1000000000000# power_name(2) = "billion": power_value(2) = 1000000000 power_name(3) = "million": power_value(3) = 1000000 power_name(4) = "thousand": power_value(4) = 1000 power_name(5) = "": power_value(5) = 1 For i = 1 To 5 ' See if we have digits in this range. If num >= power_value(i) Then ' Get the digits. digits = Int(num / power_value(i)) ' Add the digits to the result. If Len(result) > 0 Then result = result & ", " result = result & Words_1_999(digits) & " " & power_name(i) ' Get the number without these digits. num = num - digits * power_value(i) End If Next i NumbersToWords = Trim$(result) End Function ' Return words for this value between 1 and 999. Public Function Words_1_999(ByVal num As Integer) As String Dim hundreds As Integer Dim remainder As Integer Dim result As String hundreds = num \ 100 remainder = num - hundreds * 100 If hundreds > 0 Then result = Words_1_19(hundreds) & " hundred " End If If remainder > 0 Then result = result & Words_1_99(remainder) End If Words_1_999 = Trim$(result) End Function ' Return a word for this value between 1 and 19. Public Function Words_1_19(ByVal num As Integer) As String Select Case num Case 1 Words_1_19 = "one" Case 2 Words_1_19 = "two" Case 3 Words_1_19 = "three" Case 4 Words_1_19 = "four" Case 5 Words_1_19 = "five" Case 6 Words_1_19 = "six" Case 7 Words_1_19 = "seven" Case 8 Words_1_19 = "eight" Case 9 Words_1_19 = "nine" Case 10 Words_1_19 = "ten" Case 11 Words_1_19 = "eleven" Case 12 Words_1_19 = "twelve" Case 13 Words_1_19 = "thirteen" Case 14 Words_1_19 = "fourteen" Case 15 Words_1_19 = "fifteen" Case 16 Words_1_19 = "sixteen" Case 17 Words_1_19 = "seventeen" Case 18 Words_1_19 = "eightteen" Case 19 Words_1_19 = "nineteen" End Select End Function ' Return a word for this value between 1 and 99. Public Function Words_1_99(ByVal num As Integer) As String Dim result As String Dim tens As Integer tens = num \ 10 If tens <= 1 Then ' 1 <= num <= 19 result = result & " " & Words_1_19(num) Else ' 20 <= num ' Get the tens digit word. Select Case tens Case 2 result = "twenty" Case 3 result = "thirty" Case 4 result = "forty" Case 5 result = "fifty" Case 6 result = "sixty" Case 7 result = "seventy" Case 8 result = "eighty" Case 9 result = "ninety" End Select ' Add the ones digit number. result = result & " " & Words_1_19(num - tens * 10) End If Words_1_99 = Trim$(result) End Function |